Lim_x→0 e^x - e^-x - 2x / x - sinx x is equal to ???

Dear mainak,

Using L hospital rule you can obtain the following equation :

    Lim x = 0         :     ( e^x - e^-x )/sinx ;

  now again apply the same rule :

                                   :     ( e^x  + e^-x )/cosx

 The result is 2

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