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Differential Calculus

IF THE CURVE Y=AX2+BX PASSES THROUGH (-1,0) FIND Y=X IS THE TANGENT LINE AT X=1 THEN (a,b)

Profile image of giridhar reddy
16 Years agoGrade
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1 Answer

Profile image of Badiuddin askIITians.ismu Expert
16 Years ago

Dear girdhar

Y=AX2+BX

it passes through (-1,0)

so it will satisfies the given equation

0 = A -B

A=B

 

and dY/dX =2Ax + B

                     =2A +B

given dY/dX =1

             2A +B =1

             3A =1

A=1/3 =B

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