(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

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Vikas TU · Answer

What is alpha here? Alpha value is not mentioned neither the condition to find alpha. Since alpha is not mentioned dy/dx cannot be calculated.

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(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

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(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

1 Answers

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