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(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

(√1-y²)+(√1-t²)=alpha(y-t)ans x= sin^-1(t√1-t+√t√2-t²)then dy/dx=

Grade:12

1 Answers

Vikas TU
14149 Points
4 years ago
What is alpha here?
Alpha value is not mentioned neither the condition to find alpha.
Since alpha is not mentioned dy/dx cannot be calculated.

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