 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
1-the normal to a curve at p (x,y) meets the x-axis at G if the dist of G from origin is twice the abscissa of p , find curve 2- u see in this q - dy/dx( e to the power x + 1/e to the power x)+1=0 find soln as real ans is c1e to the power x + c2 e to the power -x why diff ans 3-1-the normal to a curve at p (x,y) meets the x-axis at G if the dist of G from origin is twice the abscissa of p , find curve respected sir plz check the soln again which u provid 1- find the eqn of curve which is such that the portion of the axis of x cut off b/w the origin and tangent at any pt is proportional to the ordinate of that pt

```
6 years ago

```							P(x, y) and G(2x, 0) are 2 points on the normal.

So, slope of the normal is, m=0-y2x-x=-yx

This means that the slope of the curve to which the normal was drawn is = -1m=xy

Thus, the equation of the curve is:-

Y-y=xy(X-x)i.e., Yy-y2=Xx-x2i.e., Xx-Yy=x2-y2

(2)

xy=1yx

?xyyx=1?log (xyyx)=log 1?log(xy)+log(yx)=0

?ylogx + xlogy=0?ddx(ylogx + xlogy)=ddx(0)?yx+logxdydx+logy+xydydx=0

?dydx(logx+xy)=-logy-yx?dydx=-logy+yx(logx+xy)

?dydx=-(xlogy+y)y(ylogx+x)x?dydx=-y2+xy logyx2+xy logx
```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions