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the dissociation constant of a substituted benzoic acidat25c is 1.0*10^-4.The pH of a 0.01 M solution of its sodium salt is

 
the dissociation constant of a substituted benzoic acidat25c is 1.0*10^-4.The pH of a 0.01 M solution of its sodium salt is
 
 

Grade:11

1 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
acid=AH
salt=ANa
A- + H+................=AH
C...........10^-7 M........0.....................(initially)
C-x.....x+10^-7 M........x......................(at equilibrium)
writting equilibrium constant, k=[AH]/[A-][H+]........(1)
but for the acid, the dissociation constant can be given as:
AH.............=A- +H+

Ka=[A-][H+]/[AH]=1/k.,....................(2)

Now apply (1) to get the value of H+ and hence pH.
If u have further doubt, u can post on the forum.

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