PLEASE ANSWER!!!When 2 hybrids rrtt and Rrtt are crossed the phenotypic ratio of offsprings would be???

When you cross the two hybrids rrtt and Rrtt, you're looking at a genetic scenario where one parent is homozygous recessive for both traits (rrtt) and the other is heterozygous for one trait while homozygous recessive for the other (Rrtt). To determine the phenotypic ratio of the offspring, we can break it down step by step.

Understanding the Parental Genotypes

The genotypes can be described as follows:

• Parent 1: rrtt (homozygous recessive for both traits)
• Parent 2: Rrtt (heterozygous for the first trait, homozygous recessive for the second)

Setting Up the Punnett Square

To find the offspring's genotypes, we can use a Punnett square. The alleles from each parent will form the rows and columns of the square:

• From rrtt, the gametes are rt (since both alleles are recessive).
• From Rrtt, the gametes can be Rr and rt.

The resulting Punnett square will look like this:

Analyzing the Offspring

From the Punnett square, we can see the following combinations of genotypes:

• 1 offspring with genotype Rrtt
• 1 offspring with genotype rrtt

Calculating the Phenotypic Ratio

Now, let's examine the phenotypes associated with these genotypes:

• Rrtt: expresses the dominant trait from the R allele and the recessive traits from tt.
• rrtt: expresses the recessive traits from both the r and t alleles.

Thus, the potential phenotypes are:

• 1 dominant phenotype (from Rrtt)
• 1 recessive phenotype (from rrtt)

Final Ratio

The final phenotypic ratio of the offspring resulting from this cross is 1:1. This means that for every offspring exhibiting the dominant trait, there is one offspring exhibiting the recessive trait.

In summary, when crossing the hybrids rrtt and Rrtt, the phenotypic ratio of the offspring will be 1 dominant phenotype to 1 recessive phenotype, or simply 1:1.