# If length of E. Coli DNA is 1.36 mm, what is the number of base pairs in E. Coli?

Grade:12

## 5 Answers

varun
304 Points
6 years ago
HELLO AKSHAY,
The distance between two consecutive base pairs is 0.34 X 10^-9m
The total length of double helix DNA in an organism can be calculated by multiplying the total number of base pairs with distance between two consecutive base pairs
Total length of double helix DNA = total number of base pairs X distance between two consecutive bp

Let the total number of bp be x
1.36mm = x X 0.34 X 10^-9m
by solving this we get,
= 4 X 10^6 bp
So the number of base pairs in given strand of E coli = 4 X 10^6bp
THANK YOU
Ayce Nur Yucesoy
29 Points
6 years ago
Distance between two consecutive base pairs is 0.34 × 10^-9 m
To find the number of base pairs, you need to divide the length of the distance.
Darshan
20 Points
6 years ago
Total length of given DNA = product of total number of basepairs and distance between themThis above formula is applicable for all lengths of DNA provided information is correct
Aashu Mittal
85 Points
6 years ago
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Vaibhav Bandu Bargaje
13 Points
5 years ago
To find the no of Base pairs in E.coli

Given :
Let the length of e.coli DNA is 1.36mm/1.36×10^3m
And distance between two consecutive (bp)
is
0.34 ×^-9m

Let
Length of DNA =no. of Base pairs ×distance between consecutive (bp )
1.36×10^3m =no. Of Base pairs ×0.34×10^-9m
No of Base pairs =1.36×10^3÷0.34×10^-9
By solving it
No of Base pairs =4×10^6m

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