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If an interphase cell is treated with cyanide (a metabolic poison), the cell does not divide by mitosis.? If an interphase cell is treated with cyanide (a metabolic poison), the cell does not divide by mitosis. However, if cyanide is added right after mitosis has started, the same cell completes mitosis. Which of the following explains this observation? A. Metabolic activity ceases during mitosis B. Cell division does not require metabolic activity C. Energy required for mitosis is produced and stored in the cell during interphase D. Mitotic cells make factors that make them resistant to cyanide

If an interphase cell is treated with cyanide (a metabolic poison), the cell does not divide by mitosis.?
If an interphase cell is treated with cyanide (a metabolic poison), the cell does not divide by 
mitosis. However, if cyanide is added right after mitosis has started, the same cell completes 
mitosis. Which of the following explains this observation? 
A. Metabolic activity ceases during mitosis 
B. Cell division does not require metabolic activity 
C. Energy required for mitosis is produced and stored in the cell during interphase 
D. Mitotic cells make factors that make them resistant to cyanide

Grade:12

2 Answers

sushant
31 Points
8 years ago
Option d
Debayan Dipayan Kar
26 Points
5 years ago
Option. C is correct because in cell division inter phase is more energy requiring process since in this phase the replication of DNA occurs.so if cyanide is applied to a cell in early stage of inter phase it will not get the required energy for replication and other processes.Because cyanide inhibits the transfer of electron from cyt-c and stops yielding energy.but if cyanide is applied to a cell after interphase the mitotic division will not be stopped because the required energy has already produced in inter phase.

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