Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies would
have the proportion :
(A) (p + q)²=1
(b) p²-q²-1
(c) pq = ½
(d) (p – q)²=1

Question

Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies would have the proportion : (A) (p + q) 2 =1 (b) p 2 -q 2 -1 (c) pq = ½ (d) (p – q) 2 =1

Raheema Javed · Answer

The correct answer is (A) (p+q) 2 =1. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, respectively, the expected genotype frequencies are f(AA) = p 2 for the AA homozygotes, f(aa) = q 2 for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. The genotype proportions p 2 , 2pq, and q 2 are called the Hardy-Weinberg proportions. Note that the sum of all genotype frequencies of this case is the binomial expansion of the square of the sum of p and q, and such a sum, as it represents the total of all possibilities, must be equal to 1.

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Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies would have the proportion : (A) (p + q) 2 =1 (b) p 2 -q 2 -1 (c) pq = ½ (d) (p – q) 2 =1

Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies would
have the proportion :
(A) (p + q)²=1
(b) p²-q²-1
(c) pq = ½
(d) (p – q)²=1

1 Answers

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Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies would have the proportion : (A) (p + q) 2 =1 (b) p 2 -q 2 -1 (c) pq = ½ (d) (p – q) 2 =1

Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies wouldhave the proportion :(A) (p + q)2=1(b) p2-q2-1(c) pq = ½(d) (p – q)2=1

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Agene has two al eles ëAí and ëaí with a frequency of p and q respectively the genotypic frequencies would
have the proportion :
(A) (p + q)²=1
(b) p²-q²-1
(c) pq = ½
(d) (p – q)²=1