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After a capacitor has charged for 1 tc, what percentage of current remains in the resistor? 63.2 36.8 5.0 13.5
Dear Abhishek The current in the resistor has dropped to about 36.8% of the initial charging current after one time-constant of time has elapsed. Hence option B is correct. Regards Arun (askIITians forum expert)
36.8%. Since, We know that I=i(e^-t/RC) (for charging circuit)Here, R=equivalent resistance and C=euivalent capacitance I=final current i=initial current RC=time constant . For one time constant -t/RC = 1 . Therefore, I=i(e^-1) and 1/e=36.8 . Therefore, I=36.8i .therefore answer is 36.8%.If you found this answer useful, kindly approve it.Thankyou
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