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a slab of material of dielectric constant K hs the same area as the plates of a parallel-plate capacitor but has a thickness 3d/4, where d is the seperation of the plates. how is the. capacitance changed with the slab is inserted between the plats ?

abhishek jain , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Abhishek
C = \LARGE \varepsilono *A/(d-t + t/k)
C = \LARGE \varepsilono *A/ (d- 3d/4 + 3d/4k)
C = (4k/k+3) (\LARGE \varepsilono *A /d)
C = (4k/k+3) * Co
Regards
Arun (askIITians forum expert)

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