a cross between pure breeding plant with red dots on leaves and pure breeding white dotted plant produces heterozygotes that have both red and white dots. on self pollination of F1 , what fraction of plants show both red and white dots on leaves. explain?

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Neeti · Answer

Since the F1 generation shows both white and red dots, it is a case of codominance. In codominance, both characters are expressed independently , just like AB blood group. Let Red dots genotype be RR (assuming it is dominant) and white dots plant rr Crossing the two purelines gives us F1 hybrid Rr showinbg red and white dots. the gametes produced by F1 will be R and r therefore the progeny will be RR, Rr Rr and rr where Rr is red and white dots therefore out of 4plants, 2 plants show both red and white dots so the fraction will be ½ Please feel free to ask any follow up question and approve the solution if you like it :)

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a cross between pure breeding plant with red dots on leaves and pure breeding white dotted plant produces heterozygotes that have both red and white dots. on self pollination of F1 , what fraction of plants show both red and white dots on leaves. explain?

a cross between pure breeding plant with red dots on leaves and pure breeding white dotted plant produces heterozygotes that have both red and white dots. on self pollination of F1 , what fraction of plants show both red and white dots on leaves. explain?

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a cross between pure breeding plant with red dots on leaves and pure breeding white dotted plant produces heterozygotes that have both red and white dots. on self pollination of F1 , what fraction of plants show both red and white dots on leaves. explain?

a cross between pure breeding plant with red dots on leaves and pure breeding white dotted plant produces heterozygotes that have both red and white dots. on self pollination of F1 , what fraction of plants show both red and white dots on leaves. explain?

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