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`        x +1/x=3 then find x^5+1/x^5=? Please give full explanation of this Algeria expressions sum.`
one year ago

## Answers : (4)

```							Assuming the question as (x + 1/x) = 3Squaring on both the sides we get(x + 1/x)2 = 32x2 +(1/x2) + 2 = 9⇒ x2 +(1/x2)  = 7Now cubing on both the sides we get,[x2 +(1/x2)]3  = 73LHs is in the form of (a + b)3 = a3 + b3 + 3ab (a + b)Hence [x2]3 + [(1/x2)]3 + 3 (x2) × (1/x2)[x2 +(1/x2)]  = 343⇒ x6 + (1/x6) + 3 × 7 = 343⇒ x6 + (1/x6) + 21 = 343∴  x6 + (1/x6)  = 343 − 21 = 322
```
one year ago
```							In this question i think we are asked x^5+1/x^5 Solution:x+1/x=3 so x^2+1/x^2+2=9or x^2+1/x^2=7not (x+1/x)(x^2+1/x^2)=7×3=21so x^3+1/x^3+(x+1/x)=21 or x^3+1/x^3=18Now, (x^2+1/x^2)(x^3+1/x^3)=18×7=136or x^5+1/x^5+(x+1/x)=136Finally x^5+1/x^5=133I tried my best to give the answer in simplest way as possible if you are satisfied please approve.
```
one year ago
```							X+1/X =3, thefore( x+1/x)^2=x^2+1/x^2+2 =9,so x^+x^2=7 . likewise,x^3+1/x^3=18Also,(x^2+1/x^2)(x^3+1/x^3)=x^5+1/x^5+x+1/X=18x7=126.therefore x^5+1/x^5=126-3=123  the  correct answer is 123.The rest of the steps are correct
```
11 months ago
```							x+1/x=3  (Squaring on both sides)x^2+1/x^2+2=3^2x^2+1/x^2=9-2=7 x+1/x=3(cubing on both sides) x^3+1/x^3+3(x+1/x)=3^3x^3+1/x^3=27-3(3)x^3+1/^3=18(x^2+1/x^2)(x^3+1/x^3)=x^5+1/x^5+1/x+x  (a^m*a^n=a^(m+n))                7*18=x^5+1/^5+(x+1/x)              126-(x+1/x)=x^5+1/x^5              126-3=x^5+1/x^5So x^5+1/x^5=123
```
4 months ago
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