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write the length of chord of the parabola y2=4ax that passes trough the vertex and inclined to the axis at pi/4
Dear student Vertex = (0,0)Now line will be y -0 = m(x-0)but m = tan (pi/4) = 1HenceLine:y = xNowIts intersection point with parabolay2 = 4ayy = 0 then x = 0And y = 4a then x = 4a NowIntersection point = (4a, 4a) HenceLength of chord = length between (0,0) and (4a, 4a)= 4a 2 RegardsArun (askIITians forum expert)
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