The sum of the rational terms in the binomial exp

Question

The sum of the rational terms in the binomial expansion (2^1/3+3^1/5) is.

Vikas TU · Accepted Answer

( 3^1/5 + 2^1/3)^15 = 15C0*(3^1/5)^15*(2^1/3)^0 + 15C1*(3^1/5)^14*(2^1/3)^1 + ....... + 15C15*(2^1/3)^15*(3^1/5)^0. In the first place term = 3^3 = 27. Second term = 15C1*3^14/5 * 2^1/3. 3^15/4 is unreasonable . As rational*irrational = unreasonable, second term is unreasonable. Right off the bat, we should just consider forces of 3 . A similar thing will occur in the event of every single other term with the exception of (3^1/5)^10, (3^1/5)^5 and (3^1/5)^0. At the point when energy of 3^1/5 is 10, that of 2^1/3 is 5. In any case, 2^5/3 is nonsensical so this term, as well, is silly. A similar thing occurs if there should be an occurrence of (3^1/5)^5. At the point when energy of 3^1/5 is zero, that of 2^1/3 is 15. It's a last term. Last term = 2^5 = 32. There're just 2 reasonable terms : 27 and 32. Sum of reasonable terms = 59.

Analytical Geometry> The sum of the rational terms in the bino...

The sum of the rational terms in the binomial expansion (2^1/3+3^1/5) is.

Rahul , 7 Years ago

Vikas TU

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Analytical Geometry> The sum of the rational terms in the bino...

The sum of the rational terms in the binomial expansion (2^1/3+3^1/5) is.

Rahul , 7 Years ago

Vikas TU

Provide a better Answer & Earn Cool Goodies

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