The sum of slopes of lines tangent to both the circle x^2+y^2=1 and (x-b)^2+y^2= 1

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Arun · Answer

Dear student line is y = mx ± sqrt(1+m 2 ) y = m(x-b) ± sqrt (1+m 2 ) as both lines are same hemce make theor constant part equal and hen you will get values of m. hope it helps Regards Arun (askIITians forum expert)

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The sum of slopes of lines tangent to both the circle x^2+y^2=1 and (x-b)^2+y^2= 1

The sum of slopes of lines tangent to both the circle x^2+y^2=1 and (x-b)^2+y^2= 1

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The sum of slopes of lines tangent to both the circle x^2+y^2=1 and (x-b)^2+y^2= 1

The sum of slopes of lines tangent to both the circle x^2+y^2=1 and (x-b)^2+y^2= 1

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