the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

Question

Saurabh Koranglekar · Answer

Dear student Tge two curves intersect so circle with minimum area is 0 Regards

Vikas TU · Answer

Let the radius of circle with least area be r,

Then, coordinates of centre = (0, 4 - r)

Since the circle touches the line y = x
|0-(4-r)/sqrt2| = r
so , r = 4/(sqrt2+1)
But r is not equal to 4/(1-sqrt2)
Because 4/(1-sqrt2) is less than 0
r = 4(sqrt2-1)

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the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

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the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

2 Answers

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