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Grade: 12

                        

the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

11 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
10233 Points
							Dear student

Tge two curves intersect so circle with minimum area is 0

Regards
11 months ago
Vikas TU
13786 Points
							
Let the radius of circle with least area be r,
Then, coordinates of centre = (0,  4 - r)
Since the circle touches the line y = x 
|0-(4-r)/sqrt2| = r 
so , r = 4/(sqrt2+1)
But r is not equal to 4/(1-sqrt2)
Because  4/(1-sqrt2) is less than 0 
r = 4(sqrt2-1)
11 months ago
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