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# the radius of a circle having minimum area which touches the curve y=4-x^2 and the lines y=mod(x) is

Grade:12

## 2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

Tge two curves intersect so circle with minimum area is 0

Regards
Vikas TU
14149 Points
one year ago
Let the radius of circle with least area be r,
Then, coordinates of centre = (0,  4 - r)
Since the circle touches the line y = x
|0-(4-r)/sqrt2| = r
so , r = 4/(sqrt2+1)
But r is not equal to 4/(1-sqrt2)
Because  4/(1-sqrt2) is less than 0
r = 4(sqrt2-1)

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