the number of normals to a parabola y^2 = 8x through (2,1) is

Question

Harsh Patodia · Answer

Equation of normal y = mx &ndash; 2am &ndash; am 3 here a= 2 from parabola ​Passes through (2,1) 1= 2m &ndash; ​4m &ndash; ​2m ​3 2m ​3 ​+ 2m + 1 =0 Derivate of above function is 6m ​2 + 2 which is always positive so thiswill be increasingfunction. So it will have only one root. So onenormal.​

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the number of normals to a parabola y^2 = 8x through (2,1) is

the number of normals to a parabola y^2 = 8x through (2,1) is

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