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the number of normals to a parabola y^2 = 8x through (2,1) is the number of normals to a parabola y^2 = 8x through (2,1) is
Equation of normaly = mx – 2am – am3 here a= 2 from parabolaPasses through (2,1)1= 2m – 4m – 2m32m3 + 2m + 1 =0Derivate of above function is 6m2+ 2 which is always positive so thiswill be increasingfunction. So it will have only one root.So onenormal.
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