The number of normal(s) to the parabola y^2 = 8x through (2,1) is?
akash jana , 9 Years ago
Grade 12th pass
1 Answers
Vijay Mukati
Last Activity: 9 Years ago
Dear Student, Equaiton of any normal to y2 = 4ax is y = mx -2am -am3. Now since it passes through (2,1) and a = 2. Therefore equation will be m3+2m+1 =0 Solve the cubic equation to get the number of possible real slopes. Thanks.