Grade 12th passAnalytical Geometry
The number of normal(s) to the parabola y^2 = 8x through (2,1) is?
The number of normal(s) to the parabola y^2 = 8x through (2,1) is?
1 Answer
Vijay Mukati
Approved Tutor Answer10 Years agoDear Student,
Equaiton of any normal to y2 = 4ax is y = mx -2am -am3. Now since it passes through (2,1) and a = 2. Therefore equation will be m3+2m+1 =0 Solve the cubic equation to get the number of possible real slopes.
Thanks.
Equaiton of any normal to y2 = 4ax is y = mx -2am -am3. Now since it passes through (2,1) and a = 2. Therefore equation will be m3+2m+1 =0 Solve the cubic equation to get the number of possible real slopes.
Thanks.
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