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The locus of pole of chord of parabola y^2=4ax which subttend right angle at vertex

The locus of pole of chord of parabola y^2=4ax which subttend right angle at vertex

Grade:11

1 Answers

Arun
25758 Points
4 years ago
Dear student
 
ler the pole be (x1,y1)  then polar is yy1-2a(x+x1) on homogenising with parabola we get  homogenous pair of straight lines ie           8a2-4ay1xy+2ax1y2=0 since it subtend right angle at vertex then coefficient of x2+ coefficient of y2 =0 therefore 8a2+2ax1 =0 therefore locus is x1+4a=0 , x+4a=0

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