The locus of pole of chord of parabola y^2=4ax which subttend right angle at vertex

Question

Arun · Answer

Dear student ler the pole be (x 1, y 1 ) then polar is yy 1- 2a(x+x 1 ) on homogenising with parabola we get homogenous pair of straight lines ie 8a 2 -4ay 1 xy+2ax 1 y 2 =0 since it subtend right angle at vertex then coefficient of x 2 + coefficient of y 2 =0 therefore 8a 2 +2ax 1 =0 therefore locus is x 1 +4a=0 , x+4a=0

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The locus of pole of chord of parabola y^2=4ax which subttend right angle at vertex

The locus of pole of chord of parabola y^2=4ax which subttend right angle at vertex

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