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Grade: 12th 

                        
The locus of point of intersection of tangent to parabola y`2=4ax and subtend an angle ¥ ..
3 years ago

Answers : (1)

Arun
24742 Points 
							
 
Let m1=m and m2=2m eqn of tangent of parabola=y=mx+a/m from y=4ax^2 a=a y=2m+a/2m eq1 y=mx+a/m eq2nd solving eq we get y=3mx put m=y/3x in eq 2 you get result
3 years ago
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