 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
The line 2x-y+1=0 is tangent to The circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle?
The line 2x-y+1=0 is tangent to The circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle?

```
4 years ago

```							Let eq of circle is x^+y^+2gx+2fy+c=0.  and according to question point (2,5) is a point on circle on which tangent drawn so it is satisfied in this equation.  after put it we get.     4g+10f+29+c=0. And. Centre (-g,-f) satisfy in given equation x-2y=4. So. 2f-g=4.  And the perpendicular distance from 2x-y+1=0. From centre of circle is radius.  So.  -2g+f+1/root5=root over g^+f^-c.    Now here three equation and three variable then solve it and finally answer is 3root5
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions