The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle??

Question

Rakesh · Answer

2x-y+1=0 is a tangent . Slope=-1/2Then eq. Of OA is x+2y=12According to centre of circle of coordinates(x-2y=4)We get,(8,2)R=OA=√(8-2)^2+(2-5)^2=3√5

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The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle??

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle??

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The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle??

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circle lies on x-2y=4 then what is the radius of circle??

1 Answers

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Other Related Questions on Analytical Geometry

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