The distance of a point (x1 ,y1 ) from each of the two lines which pass through the origin of coordinates is z prove that the two lines are given by (x1y-y1x) whole square =z square (xsquare+ysquare)

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Susmita · Answer

As the line passes through the origin,so equation of the line can be written as y=mx•••••(1) Or,mx-y=0 The distance d(=z) from the point (x 1 ,y 1 ) to this straight line is z=|mx 1 -y 1 |/root(m 2 +1) Taking whole square on both side z 2 (m 2 +1)=(mx 1 -y 1 ) 2 ••••••(2) From equation(1) y=mx Or,m=y/x Putting this value of m in eq(2) z 2 {(y 2 +x 2 )/x 2 }=(yx 1 -xy 1 ) 2 /x 2 or,z 2 (x 2 +y 2 )=(yx 1 -xy 1 ) 2 please approve the answer if helped.

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The distance of a point (x1 ,y1 ) from each of the two lines which pass through the origin of coordinates is z prove that the two lines are given by (x1y-y1x) whole square =z square (xsquare+ysquare)

The distance of a point (x1 ,y1 ) from each of the two lines which pass through the origin of coordinates is z prove that the two lines are given by (x1y-y1x) whole square =z square (xsquare+ysquare)

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The distance of a point (x1 ,y1 ) from each of the two lines which pass through the origin of coordinates is z prove that the two lines are given by (x1y-y1x) whole square =z square (xsquare+ysquare)

The distance of a point (x1 ,y1 ) from each of the two lines which pass through the origin of coordinates is z prove that the two lines are given by (x1y-y1x) whole square =z square (xsquare+ysquare)

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