Last Activity: 6 Years ago
BaseAB of the triangleABC, lies along x= a
ie, lies on the line // Y axis
length of base AB = 2a
& area ( triABC) = 1/2 * 2a *altitude = a²
=> altitude = a
Hence, vertices of A,B,C as follows
Coordinates of A ( a,y )
Coordinates of B ( a, 2a-y )
Coordinates of C = ( 2a, y1 ) OR ( 0,y1)
y coordintes of these vertices can hold any value..
locus of C is either Y axis or a line parallel to Y axis
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Last Activity: 2 Year ago(s)