Guest

tan38°-cot22°=?(a)1/2cosec38°sec22°(b)2sin22°cos38°(c) -1/2cosec22°sec38° (d)none

tan38°-cot22°=?(a)1/2cosec38°sec22°(b)2sin22°cos38°(c) -1/2cosec22°sec38° (d)none

Grade:10

1 Answers

manna
59 Points
7 years ago
tan38-cot22
sin38/cos38-1/tan22
now you can solve it.
Anwer is none,
but first let me show your work..where are you getting stucked

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free