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tan38°-cot22°=?(a)1/2cosec38°sec22°(b)2sin22°cos38°(c) -1/2cosec22°sec38° (d)none

tan38°-cot22°=?(a)1/2cosec38°sec22°(b)2sin22°cos38°(c) -1/2cosec22°sec38° (d)none

Grade:10

1 Answers

manna
59 Points
5 years ago
tan38-cot22
sin38/cos38-1/tan22
now you can solve it.
Anwer is none,
but first let me show your work..where are you getting stucked

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