Sir/madam, how to prove that equation of a straight line joining s and r on circle x²+y²=a² are xcos(s+r/2)+ysin(s+r/2)=acos(s-r/2) where a is the radius of the circle.also give the theory part behind it because I didn't find the explanation anywhere.

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Saurabh Koranglekar · Answer

Dear student s and r are points or angles Please write the question in a standard form or attach an image of the question Regards

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Sir/madam, how to prove that equation of a straight line joining s and r on circle x²+y²=a² are xcos(s+r/2)+ysin(s+r/2)=acos(s-r/2) where a is the radius of the circle.also give the theory part behind it because I didn't find the explanation anywhere.

Sir/madam, how to prove that equation of a straight line joining s and r on circle x²+y²=a² are
xcos(s+r/2)+ysin(s+r/2)=acos(s-r/2) where a is the radius of the circle.also give the theory part behind it because I didn't find the explanation anywhere.

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Sir/madam, how to prove that equation of a straight line joining s and r on circle x²+y²=a² are xcos(s+r/2)+ysin(s+r/2)=acos(s-r/2) where a is the radius of the circle.also give the theory part behind it because I didn't find the explanation anywhere.

Sir/madam, how to prove that equation of a straight line joining s and r on circle x²+y²=a² are xcos(s+r/2)+ysin(s+r/2)=acos(s-r/2) where a is the radius of the circle.also give the theory part behind it because I didn't find the explanation anywhere.

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Sir/madam, how to prove that equation of a straight line joining s and r on circle x²+y²=a² are
xcos(s+r/2)+ysin(s+r/2)=acos(s-r/2) where a is the radius of the circle.also give the theory part behind it because I didn't find the explanation anywhere.