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Question no. 03. What is the locus of mid point of focal chord of ellipse (x^/a^) + (y^2/b^2) =1

Anishajyoti , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

 
We have:x2a2+y2b2=1Equation of chord having mid point (h,k) isT=S1⇒hxa2+kyb2−1=h2a2+k2b2−1⇒hxa2+kyb2=h2a2+k2b2Chord passes through focus (ae,0)⇒haea2+0=h2a2+k2b2⇒h2a2+k2b2=ehaHence equation of locus is⇒x2a2+y2b2=exa

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