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Q.47 see image.........................................................

Q.47 see image.........................................................

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Grade:12

1 Answers

Aditya Gupta
2081 Points
4 years ago
r1= K/(s – h) and R= abh/4K where K is area and R is circumradius and r1 is exradius. obviously K= ab/2. so that R= h/2
so ratio R/r1= h(s – h)/2K= h(s – h)/ab= root2/(root2 + root3)
now, let a/b= x and by pythagoras a^2+b^2= h^2 or h= b*root(1+x^2)
also, 2s= a+b+h
so you can plug in these values in terms of x and you shall get the ratio. finding angles B and C is easy as tan B and tanC can be found out once the value of x is known.
kindly approve :)

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