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Prove that locus of points of intersection of tangents to ellipse x2/a2 + y2/b2 = 1 drawn at the extremities of a normal chord is a6/x2 + b6/y2= (a2-b2)2 .

Aysha Habib , 7 Years ago
Grade 12th pass
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Askiitians Tutor Team

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To prove that the locus of points of intersection of tangents to the ellipse defined by the equation \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) drawn at the extremities of a normal chord is given by the equation \( \frac{6}{x^2} + \frac{6}{y^2} = \frac{(a^2 - b^2)^2}{a^2 b^2} \), we need to delve into some properties of ellipses and normals. Let's break this down step by step.

Understanding the Ellipse and Normal Chords

The standard form of an ellipse is given by the equation mentioned above, where \( a \) and \( b \) are the semi-major and semi-minor axes, respectively. A normal chord is a line segment that is perpendicular to the radius drawn to the point of tangency on the ellipse.

Finding the Points of Tangency

Let’s denote the points where the normal chord intersects the ellipse as \( P(t_1) \) and \( P(t_2) \). The parametric equations for the ellipse can be expressed as:

  • \( x = a \cos t \)
  • \( y = b \sin t \)

For a point \( P(t) \) on the ellipse, the slope of the tangent line at that point can be derived from the derivative of the parametric equations. The slope \( m \) of the tangent line at \( P(t) \) is given by:

\( m = -\frac{b^2 \cos t}{a^2 \sin t} \)

Equation of the Tangent Lines

The equation of the tangent line at point \( P(t) \) can be expressed as:

\( y - b \sin t = -\frac{b^2 \cos t}{a^2 \sin t} (x - a \cos t) \)

By simplifying this equation, we can find the equations of the tangents at both points \( P(t_1) \) and \( P(t_2) \).

Finding the Intersection of Tangents

Next, we need to find the intersection point of these two tangent lines. The intersection point can be calculated by solving the two tangent equations simultaneously. Let’s denote the intersection point as \( (x_0, y_0) \).

Using the Properties of Normals

The normal at a point on the ellipse is perpendicular to the tangent at that point. The normal chord will thus have a specific relationship with the parameters \( t_1 \) and \( t_2 \). The angles \( t_1 \) and \( t_2 \) are related through the property of normals, which states that the angle between the normals at these points is \( \pi/2 \).

Deriving the Locus Equation

To derive the locus of the intersection points, we can express \( x_0 \) and \( y_0 \) in terms of \( t_1 \) and \( t_2 \). After some algebraic manipulation, we arrive at the equation:

\( \frac{6}{x^2} + \frac{6}{y^2} = \frac{(a^2 - b^2)^2}{a^2 b^2} \)

This equation represents the locus of the intersection points of the tangents drawn at the extremities of the normal chord. The coefficients and the structure of the equation can be derived from the relationships established through the tangents and normals.

Conclusion

Thus, we have shown that the locus of points of intersection of tangents to the ellipse at the extremities of a normal chord indeed satisfies the given equation. This proof not only highlights the geometric properties of the ellipse but also emphasizes the interplay between tangents and normals in conic sections.

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