prove that area of a parallelogram=p1*p2/sin(thetha) ,where p1,p2 are distance between 2 pairs of opposite sides and thetha is the angle between any two adjacent sides.

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Praveen Kumar Das · Answer

I have derived the formula.I got the correct answer.Thanks .Don’t need the answer now..thanks.please don’t answer.i got the answer

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prove that area of a parallelogram=p1*p2/sin(thetha) ,where p1,p2 are distance between 2 pairs of opposite sides and thetha is the angle between any two adjacent sides.

prove that area of a parallelogram=p1*p2/sin(thetha) ,where p1,p2 are distance between 2 pairs of opposite sides and thetha is the angle between any two adjacent sides.

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prove that area of a parallelogram=p1*p2/sin(thetha) ,where p1,p2 are distance between 2 pairs of opposite sides and thetha is the angle between any two adjacent sides.

prove that area of a parallelogram=p1*p2/sin(thetha) ,where p1,p2 are distance between 2 pairs of opposite sides and thetha is the angle between any two adjacent sides.

1 Answers

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Other Related Questions on Analytical Geometry

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