Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Product of the perpendiculars from (-1,2) to the pair of lines x2+kxy+3y2=0 is 4/√5,then k is

Product of the perpendiculars from (-1,2) to the pair of lines x2+kxy+3y2=0 is 4/√5,then k is

Grade:12th pass

1 Answers

Ajeet Tiwari
askIITians Faculty 86 Points
11 months ago
hello student
the value of k whenProduct of the perpendiculars from (-1,2) to the pair of lines x^2+kxy+3y^2=0 is 4/√5,then k is as solved in picture642-1915_upload 13.png
hope it will help
thankyou

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free