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Product of the perpendiculars from (-1,2) to the pair of lines x2+kxy+3y2=0 is 4/√5,then k is

Product of the perpendiculars from (-1,2) to the pair of lines x2+kxy+3y2=0 is 4/√5,then k is

Grade:12th pass

1 Answers

Ajeet Tiwari
askIITians Faculty 86 Points
3 years ago
hello student
the value of k whenProduct of the perpendiculars from (-1,2) to the pair of lines x^2+kxy+3y^2=0 is 4/√5,then k is as solved in picture642-1915_upload 13.png
hope it will help
thankyou

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