P is a variable point such that the two tyangents drawn to the ellipse x 2 /a 2 +y 2 /b 2 =1 from the point P are perpendicular to each other.Find the equation of locus of P.

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Arun · Answer

Dear student equation of tangents = y = mx ± sqrt (a^2 m^2 – b^2) Now make this in quadratic in m and then use relation m1 * m2 = – 1 hence you can find locus

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P is a variable point such that the two tyangents drawn to the ellipse x 2 /a 2 +y 2 /b 2 =1 from the point P are perpendicular to each other.Find the equation of locus of P.

P is a variable point such that the two tyangents drawn to the ellipse x²/a²+y²/b²=1 from the point P are perpendicular to each other.Find the equation of locus of P.

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P is a variable point such that the two tyangents drawn to the ellipse x 2 /a 2 +y 2 /b 2 =1 from the point P are perpendicular to each other.Find the equation of locus of P.

P is a variable point such that the two tyangents drawn to the ellipse x2/a2+y2/b2=1 from the point P are perpendicular to each other.Find the equation of locus of P.

1 Answers

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Other Related Questions on Analytical Geometry

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P is a variable point such that the two tyangents drawn to the ellipse x²/a²+y²/b²=1 from the point P are perpendicular to each other.Find the equation of locus of P.