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my qusestion issssssssssssssssssssssssssssssssssssssssssssssssif circle x2+y2-kx-12y+4=0 touches x axis then k=

Utsav Solanki , 7 Years ago
Grade 12th pass
anser 1 Answers
poonam

Last Activity: 7 Years ago

General equation of circle is x2+y2+2gx+2fy+c=0. So comparing this equation with the equation in the question we get g=-k/2. f=-6. C=4. As the circle touches x axis so G^2=c. So k^2/4=4. k=4

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