MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Let S 1 = x 2 +y 2 -4x-8y+4=0 and S 2 be its image in the line y=x , find the equation of circle touching y=x at (1,1) and its radical axes with S 2 passes through the centre of S 1

4 years ago

Answers : (1)

Vikas TU
12141 Points
							
Use all the informations given and follow the step line wise.
First find the S2 circle eqn.
For that first find the image of center of circle S1 along y=x.
U can do this by solving the eqns y=x and the eqn. woyh slope -1 and passing through center of S1.
then asssume radical axis eqn be y = mx +c and pass it through center of S1. as given.
One more information is given:
apply perpendicular distance formulae for eqn. given from center of the circle S1.
Club all the eqns. and get the suitable measure and concclude the final result.
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details