0

Guest

Courses New

Let S 1 = x 2 +y 2 -4x-8y+4=0 and S 2 be its image in the line y=x , find the equation of circle touching y=x at (1,1) and its radical axes with S 2 passes through the centre of S 1

Let S1 = x2+y2-4x-8y+4=0 and S2 be its image in the line y=x , find the equation of circle touching y=x at (1,1) and its radical axes with S2 passes through the centre of S1

Grade:11

1 Answers

Vikas TU
14149 Points
7 years ago
Use all the informations given and follow the step line wise.
First find the S2 circle eqn.
For that first find the image of center of circle S1 along y=x.
U can do this by solving the eqns y=x and the eqn. woyh slope -1 and passing through center of S1.
then asssume radical axis eqn be y = mx +c and pass it through center of S1. as given.
One more information is given:
apply perpendicular distance formulae for eqn. given from center of the circle S1.
Club all the eqns. and get the suitable measure and concclude the final result.

Think You Can Provide A Better Answer ?

Other Related Questions on Analytical Geometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More