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Let S 1 = x 2 +y 2 -4x-8y+4=0 and S 2 be its image in the line y=x , find the equation of circle touching y=x at (1,1) and its radical axes with S 2 passes through the centre of S 1
Use all the informations given and follow the step line wise.First find the S2 circle eqn.For that first find the image of center of circle S1 along y=x.U can do this by solving the eqns y=x and the eqn. woyh slope -1 and passing through center of S1.then asssume radical axis eqn be y = mx +c and pass it through center of S1. as given.One more information is given:apply perpendicular distance formulae for eqn. given from center of the circle S1.Club all the eqns. and get the suitable measure and concclude the final result.
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