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let P(x,y) be a point and let me a line if l(h,k) is the foot of perpendicular drawn from be on this line and q(Alpha, beta) is image of P in the given line then prove that (h-x)/a=(k-y)/b=-(ax+by+c)/(a^2+b^2)
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Let P(h, k) be the given point, let Q(x, y) be the foot of the perpendicular, and let O be the origin. The line can have any direction. ∠PQO = 90° Point Q lies on the circle having diameter OP. The locus of point Q: (x - 0)(x - h) + (y - 0)(y - k) = 0 x² + y² - hx - ky = 0
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