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length of y intercept on positive y axis made by the circle for which (-4,3) and (12,-1) are extremities of a diameter

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one year ago

Saurabh Koranglekar
10233 Points
```							Dear studentEqn of circle ( x-4) sqr. + ( y-2) sqr = 0.5* sqrt( 272)Y intercept = 2*( sqrt( f*f - 2))Put it in formula and get the resultRegards
```
one year ago
Vikas TU
13783 Points
```							Dear student Dear Student, The center will be ((−4+12)/2,(3−1)/2)= (4,1)and radius diameter will be =sqrt((−4−12)^2+(3+1)^2) = 272So radius = √272/2So equation is (x−4)^2+(y−1)^2= 272/4= 68Now if it cuts y axis then x = 0 16+(y−1)2=68 y −1 = √(68−16)= √52So y = 2√13 +1Regrads
```
one year ago
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• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions