In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If ∠PBR = 105°, then what is the value of ∠PAR (in degrees)?

Question

Arun · Answer

Dear student...this is very simple question. Just try to draw a figure, and then find angle. Angle PAR will be 60°.....hope it helps

Shashi Kamal · Answer

Since Point B is the intersection point of angle bisectors then it must be incentre. /_PBR=90°+Q/2 so Q=30°. Also A is the intersection point of altitudes so it will be Orthocentre then PAR=(180-30)°=150°

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In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If ∠PBR = 105°, then what is the value of ∠PAR (in degrees)?

In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If ∠PBR = 105°, then what is the value of ∠PAR (in degrees)?

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In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If ∠PBR = 105°, then what is the value of ∠PAR (in degrees)?

In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If ∠PBR = 105°, then what is the value of ∠PAR (in degrees)?

2 Answers

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