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`        In a rectangle ABCD M and n are the midpoints of the sides BC and CD respectively if angle ANM is equal to 90 degrees then AB:BC is_ ?`
2 years ago

```							MN^2=(AB/2)^2+(BC/2)^2 AN^2=BC^2+(AB/2)^2 AM^2=AB^2+(BC/2)^2 AM^2=AN^2+MN^2 => AB^2+(BC^2)/4= BC^2+(AB^2)/4+ (AB^2)/4+(BC^2)/4= => (AB^2)/2=BC^2 => (AB/BC)^2=2 => AB:BC=sqr(2):1
```
one year ago
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