if the parabola y=ax 2 -6x +b passes through (0,2) and has its tangent at x=3/2 parallel to the x-axis then 1)a=2,b=-2 2)a=2,b=2 3)a=-2,b=2 4)a=-2,b=-2

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Saurabh Koranglekar · Answer

Dear student

Please find the link below

https://www.askiitians.com/iit-jee-coordinate-geometry/tangent-to-a-parabola.aspx
and the fact that (0,2) must satisfy the equation the value of b is 2

We can determine the value of a

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if the parabola y=ax 2 -6x +b passes through (0,2) and has its tangent at x=3/2 parallel to the x-axis then 1)a=2,b=-2 2)a=2,b=2 3)a=-2,b=2 4)a=-2,b=-2

if the parabola y=ax² -6x +b passes through (0,2) and has its tangent at x=3/2 parallel to the x-axis then
1)a=2,b=-2
2)a=2,b=2
3)a=-2,b=2
4)a=-2,b=-2

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if the parabola y=ax 2 -6x +b passes through (0,2) and has its tangent at x=3/2 parallel to the x-axis then 1)a=2,b=-2 2)a=2,b=2 3)a=-2,b=2 4)a=-2,b=-2

if the parabola y=ax2 -6x +b passes through (0,2) and has its tangent at x=3/2 parallel to the x-axis then1)a=2,b=-22)a=2,b=23)a=-2,b=24)a=-2,b=-2

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if the parabola y=ax² -6x +b passes through (0,2) and has its tangent at x=3/2 parallel to the x-axis then
1)a=2,b=-2
2)a=2,b=2
3)a=-2,b=2
4)a=-2,b=-2