If the normals to the parabola y^2 = 4ax at the points t1 & t2 intersect again on the parabola at the point ‘t3’ then t1*t2 = 2 ; t3 = – (t1 + t2) and hence prove that the line joining t1 & t2 passes through a fixed point (–2a, 0).
Praveen Kumar Das , 5 Years ago
Grade 12th pass
2 Answers
Arun
Last Activity: 5 Years ago
Dear student
normal to Equation at ‘t'
y = – t x + 2at + at^3
t^3 + t(2a-x) – y = 0
as it has three roots t1, t2, t3
hence t1 + t2 + t3 = 0
hence t3 = – (t1 + t2)
Vikas TU
Last Activity: 5 Years ago
Dear student
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