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If the equation 6x^2-11xy-10y^2-19y+c=0 represents a pair of straight lines find their quarks. Also find the angle between the two lines.
If the equation 6x^2-11xy-10y^2-19y+c=0 represents a pair of straight lines find their quarks. Also find the angle between the two lines.

```
3 years ago Deepak Kumar Shringi
4404 Points
```  ```
2 years ago
```							we are given the equation of staright line 6x2-11xy-10y2-19y+c=0=> 6x2-11xy-10y2=19y-c=> 6x2-15xy+4xy-10y2=19y-c=> (3x+2y)(2x-5y)=19y-c      straight line will be of the form       3x+2y+c1=0 and 2x-5y+c2=0=>  2c1+3c2=0----------1=>  2c2-5c1= -19=>  c1c2=c      from equation 1 and 2 we get;      c1=3 and c2= -2      c1c2=c= -6      hence two lines will be 2x-5y-2=0 and 3x+2y+3=0
```
2 months ago
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