if the angle between the lines 2x^2+5xy+3y^2+6x+7y+4=0 is tan inverse(m) and a^2+b^2-ab-a-b+1≤0 then 2a+3b is

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Saurabh Koranglekar · Answer

Hello student, Please check ur question once again. I find no relation between the first and second part of your question Thanks

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if the angle between the lines 2x^2+5xy+3y^2+6x+7y+4=0 is tan inverse(m) and a^2+b^2-ab-a-b+1≤0 then 2a+3b is

if the angle between the lines 2x^2+5xy+3y^2+6x+7y+4=0 is tan inverse(m) and a^2+b^2-ab-a-b+1≤0 then 2a+3b is

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if the angle between the lines 2x^2+5xy+3y^2+6x+7y+4=0 is tan inverse(m) and a^2+b^2-ab-a-b+1≤0 then 2a+3b is

if the angle between the lines 2x^2+5xy+3y^2+6x+7y+4=0 is tan inverse(m) and a^2+b^2-ab-a-b+1≤0 then 2a+3b is

1 Answers

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