Aditya Gupta
Last Activity: 4 Years ago
let line touch ellipse at P(cosp/sqrt3, sinp/2).
eqn of ellipse at P would be 3xx1+4yy1= 1 or 3xcosp/sqrt3 + 4ysinp/2= 1
or sqrt3xcosp + 2ysinp= 1
given line 3x + 4y= -71/2
since both must be identical, we have
sqrt3*cosp/3= 2sinp/4= 1/-71/2
or cosp/sqrt3= sinp/2= 1/-71/2
hence P(cosp/sqrt3, sinp/2)= ( – 1/71/2, – 1/71/2).