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How you get y1/x1×(-q/p)=-1 in this question A variable line makes intercepts on the coordinate axes the sum of whose squares is constant and is equal to a^2. Find the locus of the foot of perpendicular from the origin to this line

How you get y1/x1×(-q/p)=-1 in this question A variable line makes intercepts on the coordinate axes the sum of whose squares is constant and is equal to a^2. Find the locus of the foot of perpendicular from the origin to this line

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
2 years ago
Dear student

Please write the Question in a standard form or attach an image of the question

Regards

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