Learn to Create a Robotic Device Using Arduino in the Free Webinar. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on Robotics (Block Chain) Learn to create a Robotic Device Using Arduino
30th Jan @ 5:00PM for Grade 1 to 10
how to prove that that length of focal chord of standard ellipse(a>b) which inclined angle titha to the major axis is 2ab^2/(a^2sin^2titha+b^2cos^2titha how to prove that that length of focal chord of standard ellipse(a>b) which inclined angle titha to the major axis is 2ab^2/(a^2sin^2titha+b^2cos^2titha
Equation of focal chord inclined at angle titha with x axis is y = tantitha(x-ae)Let it intersect x^2/a^2 + y^2/b^2 = 1 at P(x1.y1) & Q(x2,y2). Solving we getb^2*x^2 + a^2*tan^2titha*(x-ae)^2 = a^2*b^2This is a quadratic equation in x. It's roots are x1 & x2.abs(x1-x2) = sqrt( x1+x2)^2-4 x1 x2) =2ab^2 sectitha/b^2+a^2tan^2titha abs(y1-y2) =abs( (x1-ae)tantitha-(x2-ae) tantitha) = abs( (x1-x2)tantitha)Lenght of focal chord = PQ = sqrt( (x1-x2)^2+(y1-y2)^2)) = 2ab^2/b^2cos^2titha+a^2sin^2titha
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -