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How did we get q=4*(3)^1/2 in the question: "A rhombus is inscribed in the region common to the two circles x 2+ y 2 -4x-12=0 and x 2+ y 2 +4x-12=0 with two of its vertices on the line joining the centres of the circles. The area of the rhombus is?"

How did we get q=4*(3)^1/2 in the question: "A rhombus is inscribed in the region common to the two circles x2+y2-4x-12=0 and x2+y2+4x-12=0 with two of its vertices on the line joining the centres of the circles. The area of the rhombus is?"

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