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`        Help please...............................................................`
2 years ago

```							Equation of tangent in slope form is               y=mx + a/m                         :-1This equation represents 2 lines.Let the external point be (g,f)Putting this in equation 1, we get             f=(g)m +a/(m)Solving we get,           (g)(m^2) -(f)(m) +a=0.           :-2      Given that       x1+x2=45°x1 and x2 are angles of tangents with x- axis thus tan of the angles represents their slopes.            tan(x1+x2)=tan 45° ( tan x1 +tan x2)/[1-(tan x1 tan x2)]=1.   :-3From the quadratic equation 2 we get          tan x1 + tan x2=(f)/g.          :-4                 tan x1 tan x2=a/g.        :-5  Putting 4,5 in 3 we have                  f=g-a   From equation of parabola y^2=4x we have a=1                 f=g-1                 g-f-1=0The locus of all such points is                 x-y-1=0Hope it will help you.
```
2 years ago
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