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ankesh singh Grade:
        
he value of k if the lines (2x+3y+4)+k(6x-y+12)=0 are parallel to y- axis
3 years ago

Answers : (1)

Rinkoo Gupta
askIITians Faculty
80 Points
										The eq. can be written as
(2+6k)x+(3-k)y+(4+12k) =0
slope of eq. = -(2+6k)/(3-k)
since it is parallel to y axis so slope of the eq. is infinity.
Hence 3-k=0
so k=3
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
3 years ago
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