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question mark

he value of k if the lines (2x+3y+4)+k(6x-y+12)=0 are parallel to y- axis

ankesh singh , 11 Years ago
Grade
anser 1 Answers
Rinkoo Gupta
The eq. can be written as
(2+6k)x+(3-k)y+(4+12k) =0
slope of eq. = -(2+6k)/(3-k)
since it is parallel to y axis so slope of the eq. is infinity.
Hence 3-k=0
so k=3
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Last Activity: 11 Years ago
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