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he value of k if the lines (2x+3y+4)+k(6x-y+12)=0 are parallel to y- axis

he value of k if the lines (2x+3y+4)+k(6x-y+12)=0 are parallel to y- axis

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1 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
7 years ago
The eq. can be written as
(2+6k)x+(3-k)y+(4+12k) =0
slope of eq. = -(2+6k)/(3-k)
since it is parallel to y axis so slope of the eq. is infinity.
Hence 3-k=0
so k=3
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty

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