From a point (h,k), h((a 2 +b 2 )/a) from which only three distinct normals can be drawn to the hyperbola x 2 /a 2 – y 2 /b 2 =1, normals are drawn to curve ((x 2 /a 2 – y 2 /b 2 ) 2 -1)(x 2 /a 2 – y 2 /b 2 )=0. Find the sum of abscissa of foot of all such normals?

Question

From a point (h,k), h>((a 2 +b 2 )/a) from which only three distinct normals can be drawn to the hyperbola x 2 /a 2 &ndash; y 2 /b 2 =1, normals are drawn to curve ((x 2 /a 2 &ndash; y 2 /b 2 ) 2 -1)(x 2 /a 2 &ndash; y 2 /b 2 )=0. Find the sum of abscissa of foot of all such normals?

Saurabh Koranglekar · Answer

((x2/a2&ndash; y2/b2)2-1) ?? Dear student The curve is not defined in correct manner Kindly repost the question with an image Regards

Vikas TU · Answer

Dear student Question is not clear Please attach an image, We will happy to help you Good Luck Cheers

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From a point (h,k), h>((a 2 +b 2 )/a) from which only three distinct normals can be drawn to the hyperbola x 2 /a 2 – y 2 /b 2 =1, normals are drawn to curve ((x 2 /a 2 – y 2 /b 2 ) 2 -1)(x 2 /a 2 – y 2 /b 2 )=0. Find the sum of abscissa of foot of all such normals?

From a point (h,k), h>((a²+b²)/a) from which only three distinct normals can be drawn to the hyperbola x²/a² – y²/b²=1, normals are drawn to curve ((x²/a² – y²/b²)²-1)(x²/a² – y²/b²)=0. Find the sum of abscissa of foot of all such normals?

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